10101111111983 has 2 divisors, whose sum is σ = 10101111111984. Its totient is φ = 10101111111982.

The previous prime is 10101111111967. The next prime is 10101111111997. The reversal of 10101111111983 is 38911111110101.

It is a strong prime.

It is an emirp because it is prime and its reverse (38911111110101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10101111111983 - 2⁴ = 10101111111967 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10101111111943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050555555991 + 5050555555992.

It is an arithmetic number, because the mean of its divisors is an integer number (5050555555992).

Almost surely, 2^{10101111111983} is an apocalyptic number.

10101111111983 is a deficient number, since it is larger than the sum of its proper divisors (1).

10101111111983 is an equidigital number, since it uses as much as digits as its factorization.

10101111111983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 29.

The spelling of 10101111111983 in words is "ten trillion, one hundred one billion, one hundred eleven million, one hundred eleven thousand, nine hundred eighty-three".