10101120022021 has 4 divisors (see below), whose sum is σ = 11544137168032. Its totient is φ = 8658102876012.

The previous prime is 10101120021989. The next prime is 10101120022057. The reversal of 10101120022021 is 12022002110101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10101120022021 - 2⁵ = 10101120021989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10101120021992 and 10101120022010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10101120062021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 721508572995 + ... + 721508573008.

It is an arithmetic number, because the mean of its divisors is an integer number (2886034292008).

Almost surely, 2^{10101120022021} is an apocalyptic number.

It is an amenable number.

10101120022021 is a deficient number, since it is larger than the sum of its proper divisors (1443017146011).

10101120022021 is an equidigital number, since it uses as much as digits as its factorization.

10101120022021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1443017146010.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 10101120022021 its reverse (12022002110101), we get a palindrome (22123122132122).

The spelling of 10101120022021 in words is "ten trillion, one hundred one billion, one hundred twenty million, twenty-two thousand, twenty-one".