Base | Representation |
---|---|
bin | 10010110100001001… |
… | …10001000000010011 |
3 | 222001222001201222022 |
4 | 21122010301000103 |
5 | 131141342231311 |
6 | 4350154202055 |
7 | 505213134212 |
oct | 113204610023 |
9 | 28058051868 |
10 | 10101133331 |
11 | 431390aa83 |
12 | 1b5aa2332b |
13 | c4c939a93 |
14 | 6bb76b079 |
15 | 3e1bd85db |
hex | 25a131013 |
10101133331 has 2 divisors, whose sum is σ = 10101133332. Its totient is φ = 10101133330.
The previous prime is 10101133303. The next prime is 10101133333. The reversal of 10101133331 is 13333110101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10101133331 - 214 = 10101116947 is a prime.
It is a super-3 number, since 3×101011333313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
Together with 10101133333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10101133333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050566665 + 5050566666.
It is an arithmetic number, because the mean of its divisors is an integer number (5050566666).
Almost surely, 210101133331 is an apocalyptic number.
10101133331 is a deficient number, since it is larger than the sum of its proper divisors (1).
10101133331 is an equidigital number, since it uses as much as digits as its factorization.
10101133331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 10101133331 its reverse (13333110101), we get a palindrome (23434243432).
It can be divided in two parts, 10101 and 133331, that multiplied together give a palindrome (1346776431).
The spelling of 10101133331 in words is "ten billion, one hundred one million, one hundred thirty-three thousand, three hundred thirty-one".
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