Base | Representation |
---|---|
bin | 10010110100001010… |
… | …11111010111000111 |
3 | 222001222102101102202 |
4 | 21122011133113013 |
5 | 131141414320312 |
6 | 4350202225115 |
7 | 505214554613 |
oct | 113205372707 |
9 | 28058371382 |
10 | 10101323207 |
11 | 4313a2a6a8 |
12 | 1b5aab519b |
13 | c4c9a5331 |
14 | 6bb7ba343 |
15 | 3e1c249c2 |
hex | 25a15f5c7 |
10101323207 has 2 divisors, whose sum is σ = 10101323208. Its totient is φ = 10101323206.
The previous prime is 10101323161. The next prime is 10101323209. The reversal of 10101323207 is 70232310101.
It is a strong prime.
It is an emirp because it is prime and its reverse (70232310101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10101323207 - 216 = 10101257671 is a prime.
Together with 10101323209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10101323209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050661603 + 5050661604.
It is an arithmetic number, because the mean of its divisors is an integer number (5050661604).
Almost surely, 210101323207 is an apocalyptic number.
10101323207 is a deficient number, since it is larger than the sum of its proper divisors (1).
10101323207 is an equidigital number, since it uses as much as digits as its factorization.
10101323207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 10101323207 its reverse (70232310101), we get a palindrome (80333633308).
The spelling of 10101323207 in words is "ten billion, one hundred one million, three hundred twenty-three thousand, two hundred seven".
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