10102006050041 has 2 divisors, whose sum is σ = 10102006050042. Its totient is φ = 10102006050040.

The previous prime is 10102006050001. The next prime is 10102006050043. The reversal of 10102006050041 is 14005060020101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7676246524816 + 2425759525225 = 2770604^2 + 1557485^2 .

It is an emirp because it is prime and its reverse (14005060020101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10102006050041 is a prime.

It is a super-2 number, since 2×10102006050041² (a number of 27 digits) contains 22 as substring.

Together with 10102006050043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10102006049995 and 10102006050022.

It is not a weakly prime, because it can be changed into another prime (10102006050043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5051003025020 + 5051003025021.

It is an arithmetic number, because the mean of its divisors is an integer number (5051003025021).

Almost surely, 2^{10102006050041} is an apocalyptic number.

It is an amenable number.

10102006050041 is a deficient number, since it is larger than the sum of its proper divisors (1).

10102006050041 is an equidigital number, since it uses as much as digits as its factorization.

10102006050041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 10102006050041 its reverse (14005060020101), we get a palindrome (24107066070142).

It can be divided in two parts, 101020060 and 50041, that added together give a palindrome (101070101).

The spelling of 10102006050041 in words is "ten trillion, one hundred two billion, six million, fifty thousand, forty-one".