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10102032202183 is a prime number
BaseRepresentation
bin1001001100000001000000…
…0010100111100111000111
31022202202002222211011101121
42103000100002213213013
52311002430220432213
633252450505134411
72061563526634435
oct223002002474707
938682088734347
1010102032202183
11324527a900759
121171a1218a407
135838049a875c
1426cd2602bd55
15127b9c7a188d
hex930100a79c7

10102032202183 has 2 divisors, whose sum is σ = 10102032202184. Its totient is φ = 10102032202182.

The previous prime is 10102032202091. The next prime is 10102032202187. The reversal of 10102032202183 is 38120223020101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10102032202183 - 221 = 10102030105031 is a prime.

It is a super-2 number, since 2×101020322021832 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10102032202187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5051016101091 + 5051016101092.

It is an arithmetic number, because the mean of its divisors is an integer number (5051016101092).

Almost surely, 210102032202183 is an apocalyptic number.

10102032202183 is a deficient number, since it is larger than the sum of its proper divisors (1).

10102032202183 is an equidigital number, since it uses as much as digits as its factorization.

10102032202183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 10102032202183 its reverse (38120223020101), we get a palindrome (48222255222284).

The spelling of 10102032202183 in words is "ten trillion, one hundred two billion, thirty-two million, two hundred two thousand, one hundred eighty-three".