101030400000413 has 16 divisors (see below), whose sum is σ = 108903678508800. Its totient is φ = 93171656976960.

The previous prime is 101030400000401. The next prime is 101030400000557. The reversal of 101030400000413 is 314000004030101.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101030400000413 is a prime.

It is a super-3 number, since 3×101030400000413³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101030400000391 and 101030400000400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101030400000613) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 515439518 + ... + 515635488.

It is an arithmetic number, because the mean of its divisors is an integer number (6806479906800).

Almost surely, 2^{101030400000413} is an apocalyptic number.

101030400000413 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

101030400000413 is a deficient number, since it is larger than the sum of its proper divisors (7873278508387).

101030400000413 is a wasteful number, since it uses less digits than its factorization.

101030400000413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 232852.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 101030400000413 its reverse (314000004030101), we get a palindrome (415030404030514).

The spelling of 101030400000413 in words is "one hundred one trillion, thirty billion, four hundred million, four hundred thirteen", and thus it is an aban number.