Base | Representation |
---|---|
bin | 11101011010000101110… |
… | …11100111111111100011 |
3 | 10120121010022120121220012 |
4 | 32231002323213333203 |
5 | 113023340200203443 |
6 | 2052105001035135 |
7 | 133000436223545 |
oct | 16550273477743 |
9 | 3517108517805 |
10 | 1010440241123 |
11 | 35a5861a0645 |
12 | 1439b6485aab |
13 | 74390246b01 |
14 | 36c96c47695 |
15 | 1b43d0d6118 |
hex | eb42ee7fe3 |
1010440241123 has 4 divisors (see below), whose sum is σ = 1020444600048. Its totient is φ = 1000435882200.
The previous prime is 1010440241101. The next prime is 1010440241219. The reversal of 1010440241123 is 3211420440101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1010440241123 - 210 = 1010440240099 is a prime.
It is a super-2 number, since 2×10104402411232 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1010440241423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5002179311 + ... + 5002179512.
It is an arithmetic number, because the mean of its divisors is an integer number (255111150012).
Almost surely, 21010440241123 is an apocalyptic number.
1010440241123 is a deficient number, since it is larger than the sum of its proper divisors (10004358925).
1010440241123 is a wasteful number, since it uses less digits than its factorization.
1010440241123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10004358924.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1010440241123 its reverse (3211420440101), we get a palindrome (4221860681224).
The spelling of 1010440241123 in words is "one trillion, ten billion, four hundred forty million, two hundred forty-one thousand, one hundred twenty-three".
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