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10104433141 = 1129307103177
BaseRepresentation
bin10010110100100010…
…10110100111110101
3222002012021101110111
421122101112213311
5131143213330031
64350353023021
7505253156515
oct113221264765
928065241414
1010104433141
1143157641a0
121b5bb54a71
13c50523a2a
146bbd89845
153e213b1b1
hex25a4569f5

10104433141 has 16 divisors (see below), whose sum is σ = 11440376640. Its totient is φ = 8840119680.

The previous prime is 10104433127. The next prime is 10104433147. The reversal of 10104433141 is 14133440101.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 10104433141 - 217 = 10104302069 is a prime.

It is a super-3 number, since 3×101044331413 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10104433147) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46345 + ... + 149521.

It is an arithmetic number, because the mean of its divisors is an integer number (715023540).

Almost surely, 210104433141 is an apocalyptic number.

10104433141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

10104433141 is a deficient number, since it is larger than the sum of its proper divisors (1335943499).

10104433141 is a wasteful number, since it uses less digits than its factorization.

10104433141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103524.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 10104433141 its reverse (14133440101), we get a palindrome (24237873242).

The spelling of 10104433141 in words is "ten billion, one hundred four million, four hundred thirty-three thousand, one hundred forty-one".

Divisors: 1 11 29 307 319 3377 8903 97933 103177 1134947 2992133 31675339 32913463 348428729 918584831 10104433141