10110009999653 has 2 divisors, whose sum is σ = 10110009999654. Its totient is φ = 10110009999652.

The previous prime is 10110009999623. The next prime is 10110009999671. The reversal of 10110009999653 is 35699990001101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6898806927364 + 3211203072289 = 2626558^2 + 1791983^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110009999653 - 2¹⁰ = 10110009998629 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110009999595 and 10110009999604.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110009999623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055004999826 + 5055004999827.

It is an arithmetic number, because the mean of its divisors is an integer number (5055004999827).

Almost surely, 2^{10110009999653} is an apocalyptic number.

It is an amenable number.

10110009999653 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110009999653 is an equidigital number, since it uses as much as digits as its factorization.

10110009999653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 590490, while the sum is 53.

The spelling of 10110009999653 in words is "ten trillion, one hundred ten billion, nine million, nine hundred ninety-nine thousand, six hundred fifty-three".