Search a number
-
+
101100112110112 = 253159378503441
BaseRepresentation
bin10110111111001100110100…
…010001001110001000100000
3111020222002001122100002011211
4112333030310101032020200
5101222411012200010422
6555004430023115504
730203146011610363
oct2677146421161040
9436862048302154
10101100112110112
112a239353680155
12b409a66ba2b94
134454913214b5b
141ad73b31400da
15ba4ca5018577
hex5bf33444e220

101100112110112 has 12 divisors (see below), whose sum is σ = 199040845716846. Its totient is φ = 50550056055040.

The previous prime is 101100112110061. The next prime is 101100112110133. The reversal of 101100112110112 is 211011211001101.

It can be written as a sum of positive squares in only one way, i.e., 96894807242256 + 4205304867856 = 9843516^2 + 2050684^2 .

It is a junction number, because it is equal to n+sod(n) for n = 101100112110092 and 101100112110101.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1579689251689 + ... + 1579689251752.

Almost surely, 2101100112110112 is an apocalyptic number.

It is an amenable number.

101100112110112 is a deficient number, since it is larger than the sum of its proper divisors (97940733606734).

101100112110112 is an equidigital number, since it uses as much as digits as its factorization.

101100112110112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3159378503451 (or 3159378503443 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 101100112110112 its reverse (211011211001101), we get a palindrome (312111323111213).

The spelling of 101100112110112 in words is "one hundred one trillion, one hundred billion, one hundred twelve million, one hundred ten thousand, one hundred twelve".

Divisors: 1 2 4 8 16 32 3159378503441 6318757006882 12637514013764 25275028027528 50550056055056 101100112110112