10110011320034 has 4 divisors (see below), whose sum is σ = 15165016980054. Its totient is φ = 5055005660016.

The previous prime is 10110011320007. The next prime is 10110011320043. The reversal of 10110011320034 is 43002311001101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 5215947984025 + 4894063336009 = 2283845^2 + 2212253^2 .

It is a super-2 number, since 2×10110011320034² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10110011319994 and 10110011320021.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527502830007 + ... + 2527502830010.

Almost surely, 2^{10110011320034} is an apocalyptic number.

10110011320034 is a deficient number, since it is larger than the sum of its proper divisors (5055005660020).

10110011320034 is an equidigital number, since it uses as much as digits as its factorization.

10110011320034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5055005660019.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10110011320034 its reverse (43002311001101), we get a palindrome (53112322321135).

The spelling of 10110011320034 in words is "ten trillion, one hundred ten billion, eleven million, three hundred twenty thousand, thirty-four".