Base | Representation |
---|---|
bin | 101111000101000001… |
… | …0010110110001000001 |
3 | 100122221211201021202121 |
4 | 1132022002112301001 |
5 | 3124023112334103 |
6 | 114240022244241 |
7 | 10206232564543 |
oct | 1361202266101 |
9 | 318854637677 |
10 | 101100121153 |
11 | 39970423439 |
12 | 17716286681 |
13 | 96c27035c5 |
14 | 4c711d1693 |
15 | 296aae66bd |
hex | 178a096c41 |
101100121153 has 2 divisors, whose sum is σ = 101100121154. Its totient is φ = 101100121152.
The previous prime is 101100121121. The next prime is 101100121207. The reversal of 101100121153 is 351121001101.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67167533889 + 33932587264 = 259167^2 + 184208^2 .
It is a cyclic number.
It is not a de Polignac number, because 101100121153 - 25 = 101100121121 is a prime.
It is not a weakly prime, because it can be changed into another prime (101100121103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550060576 + 50550060577.
It is an arithmetic number, because the mean of its divisors is an integer number (50550060577).
Almost surely, 2101100121153 is an apocalyptic number.
It is an amenable number.
101100121153 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100121153 is an equidigital number, since it uses as much as digits as its factorization.
101100121153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30, while the sum is 16.
Adding to 101100121153 its reverse (351121001101), we get a palindrome (452221122254).
The spelling of 101100121153 in words is "one hundred one billion, one hundred million, one hundred twenty-one thousand, one hundred fifty-three".
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