101100131141 has 2 divisors, whose sum is σ = 101100131142. Its totient is φ = 101100131140.

The previous prime is 101100131021. The next prime is 101100131201. The reversal of 101100131141 is 141131001101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88318924225 + 12781206916 = 297185^2 + 113054^2 .

It is an emirp because it is prime and its reverse (141131001101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101100131141 - 2¹⁸ = 101099868997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101100131641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550065570 + 50550065571.

It is an arithmetic number, because the mean of its divisors is an integer number (50550065571).

Almost surely, 2^101100131141 is an apocalyptic number.

It is an amenable number.

101100131141 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100131141 is an equidigital number, since it uses as much as digits as its factorization.

101100131141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 101100131141 its reverse (141131001101), we get a palindrome (242231132242).

The spelling of 101100131141 in words is "one hundred one billion, one hundred million, one hundred thirty-one thousand, one hundred forty-one".