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101100133433 = 1341271699931
BaseRepresentation
bin101111000101000001…
…0011001110000111001
3100122221211201220121102
41132022002121300321
53124023113232213
6114240022421145
710206232645415
oct1361202316071
9318854656542
10101100133433
1139970431692
12177162917b5
1396c2709080
144c711d5d45
15296aaea158
hex178a099c39

101100133433 has 16 divisors (see below), whose sum is σ = 111944324352. Its totient is φ = 90710928000.

The previous prime is 101100133423. The next prime is 101100133493. The reversal of 101100133433 is 334331001101.

It is a cyclic number.

It is not a de Polignac number, because 101100133433 - 28 = 101100133177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101100133423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 205523 + ... + 494408.

It is an arithmetic number, because the mean of its divisors is an integer number (6996520272).

Almost surely, 2101100133433 is an apocalyptic number.

101100133433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

101100133433 is a deficient number, since it is larger than the sum of its proper divisors (10844190919).

101100133433 is a wasteful number, since it uses less digits than its factorization.

101100133433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 700256.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 101100133433 its reverse (334331001101), we get a palindrome (435431134534).

The spelling of 101100133433 in words is "one hundred one billion, one hundred million, one hundred thirty-three thousand, four hundred thirty-three".

Divisors: 1 13 41 271 533 3523 11111 144443 699931 9099103 28697171 189681301 373063223 2465856913 7776933341 101100133433