10110023117 has 2 divisors, whose sum is σ = 10110023118. Its totient is φ = 10110023116.

The previous prime is 10110023107. The next prime is 10110023179. The reversal of 10110023117 is 71132001101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6592465636 + 3517557481 = 81194^2 + 59309^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110023117 - 2¹⁰ = 10110022093 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110023095 and 10110023104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110023107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055011558 + 5055011559.

It is an arithmetic number, because the mean of its divisors is an integer number (5055011559).

Almost surely, 2^10110023117 is an apocalyptic number.

It is an amenable number.

10110023117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110023117 is an equidigital number, since it uses as much as digits as its factorization.

10110023117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 17.

Adding to 10110023117 its reverse (71132001101), we get a palindrome (81242024218).

The spelling of 10110023117 in words is "ten billion, one hundred ten million, twenty-three thousand, one hundred seventeen".