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10110041351 = 13197664929
BaseRepresentation
bin10010110101001101…
…01111110100000111
3222002120211022110222
421122212233310013
5131201132310401
64351113134555
7505351635134
oct113246576407
928076738428
1010110041351
114318944783
121b619ba45b
13c517385b7
146bca0958b
153e2897c1b
hex25a9afd07

10110041351 has 4 divisors (see below), whose sum is σ = 10117707600. Its totient is φ = 10102375104.

The previous prime is 10110041327. The next prime is 10110041387. The reversal of 10110041351 is 15314001101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10110041351 is a prime.

It is a super-2 number, since 2×101100413512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10110041311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3831146 + ... + 3833783.

It is an arithmetic number, because the mean of its divisors is an integer number (2529426900).

Almost surely, 210110041351 is an apocalyptic number.

10110041351 is a deficient number, since it is larger than the sum of its proper divisors (7666249).

10110041351 is an equidigital number, since it uses as much as digits as its factorization.

10110041351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7666248.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 10110041351 its reverse (15314001101), we get a palindrome (25424042452).

The spelling of 10110041351 in words is "ten billion, one hundred ten million, forty-one thousand, three hundred fifty-one".

Divisors: 1 1319 7664929 10110041351