101100560501 has 2 divisors, whose sum is σ = 101100560502. Its totient is φ = 101100560500.

The previous prime is 101100560471. The next prime is 101100560503. The reversal of 101100560501 is 105065001101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86265564100 + 14834996401 = 293710^2 + 121799^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101100560501 is a prime.

It is a super-2 number, since 2×101100560501² (a number of 23 digits) contains 22 as substring.

Together with 101100560503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101100560503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550280250 + 50550280251.

It is an arithmetic number, because the mean of its divisors is an integer number (50550280251).

Almost surely, 2^101100560501 is an apocalyptic number.

It is an amenable number.

101100560501 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100560501 is an equidigital number, since it uses as much as digits as its factorization.

101100560501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150, while the sum is 20.

Adding to 101100560501 its reverse (105065001101), we get a palindrome (206165561602).

The spelling of 101100560501 in words is "one hundred one billion, one hundred million, five hundred sixty thousand, five hundred one".