10110100000051 has 2 divisors, whose sum is σ = 10110100000052. Its totient is φ = 10110100000050.

The previous prime is 10110100000027. The next prime is 10110100000069. The reversal of 10110100000051 is 15000000101101.

It is a strong prime.

It is an emirp because it is prime and its reverse (15000000101101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10110100000051 - 2³³ = 10101510065459 is a prime.

It is a super-2 number, since 2×10110100000051² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10110099999983 and 10110100000037.

It is not a weakly prime, because it can be changed into another prime (10110100000751) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055050000025 + 5055050000026.

It is an arithmetic number, because the mean of its divisors is an integer number (5055050000026).

Almost surely, 2^{10110100000051} is an apocalyptic number.

10110100000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110100000051 is an equidigital number, since it uses as much as digits as its factorization.

10110100000051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5, while the sum is 10.

Adding to 10110100000051 its reverse (15000000101101), we get a palindrome (25110100101152).

The spelling of 10110100000051 in words is "ten trillion, one hundred ten billion, one hundred million, fifty-one", and thus it is an aban number.