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101101100101013 is a prime number
BaseRepresentation
bin10110111111001101101111…
…001010000110110110010101
3111020222011121111102012220102
4112333031233022012312111
5101222420023111213023
6555005112035143445
730203212336443335
oct2677155712066625
9436864544365812
10101101100101013
112a239810341361
12b40a0a1a44b85
134454a3cb08b5c
141ad74684430c5
15ba4d11b26628
hex5bf36f286d95

101101100101013 has 2 divisors, whose sum is σ = 101101100101014. Its totient is φ = 101101100101012.

The previous prime is 101101100101007. The next prime is 101101100101051. The reversal of 101101100101013 is 310101001101101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86299975289284 + 14801124811729 = 9289778^2 + 3847223^2 .

It is a cyclic number.

It is not a de Polignac number, because 101101100101013 - 28 = 101101100100757 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101101100100985 and 101101100101003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101101100101073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550550050506 + 50550550050507.

It is an arithmetic number, because the mean of its divisors is an integer number (50550550050507).

Almost surely, 2101101100101013 is an apocalyptic number.

It is an amenable number.

101101100101013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101101100101013 is an equidigital number, since it uses as much as digits as its factorization.

101101100101013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 101101100101013 its reverse (310101001101101), we get a palindrome (411202101202114).

The spelling of 101101100101013 in words is "one hundred one trillion, one hundred one billion, one hundred million, one hundred one thousand, thirteen".