1011020022013 has 4 divisors (see below), whose sum is σ = 1011022566400. Its totient is φ = 1011017477628.

The previous prime is 1011020022011. The next prime is 1011020022073. The reversal of 1011020022013 is 3102200201101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1011020022013 - 2¹ = 1011020022011 is a prime.

It is a super-4 number, since 4×1011020022013⁴ (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011020021984 and 1011020022002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011020022011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532995 + ... + 1518592.

It is an arithmetic number, because the mean of its divisors is an integer number (252755641600).

Almost surely, 2^{1011020022013} is an apocalyptic number.

It is an amenable number.

1011020022013 is a deficient number, since it is larger than the sum of its proper divisors (2544387).

1011020022013 is an equidigital number, since it uses as much as digits as its factorization.

1011020022013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2544386.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1011020022013 its reverse (3102200201101), we get a palindrome (4113220223114).

The spelling of 1011020022013 in words is "one trillion, eleven billion, twenty million, twenty-two thousand, thirteen".