10110212101111 has 4 divisors (see below), whose sum is σ = 10110226130992. Its totient is φ = 10110198071232.

The previous prime is 10110212101109. The next prime is 10110212101169. The reversal of 10110212101111 is 11110121201101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10110212101111 - 2¹ = 10110212101109 is a prime.

It is a super-3 number, since 3×10110212101111³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10110212101091 and 10110212101100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10110212107111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5871930 + ... + 7395943.

It is an arithmetic number, because the mean of its divisors is an integer number (2527556532748).

Almost surely, 2^{10110212101111} is an apocalyptic number.

10110212101111 is a deficient number, since it is larger than the sum of its proper divisors (14029881).

10110212101111 is an equidigital number, since it uses as much as digits as its factorization.

10110212101111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14029880.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 10110212101111 its reverse (11110121201101), we get a palindrome (21220333302212).

The spelling of 10110212101111 in words is "ten trillion, one hundred ten billion, two hundred twelve million, one hundred one thousand, one hundred eleven".