Base | Representation |
---|---|
bin | 111100010000101… |
… | …111011000000101 |
3 | 2121110102012111222 |
4 | 330100233120011 |
5 | 4032310140232 |
6 | 244153410125 |
7 | 34024353005 |
oct | 7420573005 |
9 | 2543365458 |
10 | 1011021317 |
11 | 479771309 |
12 | 242709945 |
13 | 1315c8887 |
14 | 983ba005 |
15 | 5db5bd12 |
hex | 3c42f605 |
1011021317 has 2 divisors, whose sum is σ = 1011021318. Its totient is φ = 1011021316.
The previous prime is 1011021301. The next prime is 1011021329. The reversal of 1011021317 is 7131201101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 642419716 + 368601601 = 25346^2 + 19199^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011021317 - 24 = 1011021301 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1011021295 and 1011021304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011021377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505510658 + 505510659.
It is an arithmetic number, because the mean of its divisors is an integer number (505510659).
Almost surely, 21011021317 is an apocalyptic number.
It is an amenable number.
1011021317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011021317 is an equidigital number, since it uses as much as digits as its factorization.
1011021317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 17.
The square root of 1011021317 is about 31796.5614021391. The cubic root of 1011021317 is about 1003.6603577669.
Adding to 1011021317 its reverse (7131201101), we get a palindrome (8142222418).
The spelling of 1011021317 in words is "one billion, eleven million, twenty-one thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •