Search a number
-
+
10110240013 is a prime number
BaseRepresentation
bin10010110101001111…
…00000010100001101
3222002121012101222211
421122213200110031
5131201210140023
64351121310421
7505353423256
oct113247402415
928077171884
1010110240013
114318a6aa65
121b61a95411
13c517a7b53
146bca5bb2d
153e28d6a0d
hex25a9e050d

10110240013 has 2 divisors, whose sum is σ = 10110240014. Its totient is φ = 10110240012.

The previous prime is 10110240001. The next prime is 10110240029. The reversal of 10110240013 is 31004201101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6699913609 + 3410326404 = 81853^2 + 58398^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110240013 - 29 = 10110239501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110239975 and 10110240002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110240053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055120006 + 5055120007.

It is an arithmetic number, because the mean of its divisors is an integer number (5055120007).

Almost surely, 210110240013 is an apocalyptic number.

It is an amenable number.

10110240013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110240013 is an equidigital number, since it uses as much as digits as its factorization.

10110240013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10110240013 its reverse (31004201101), we get a palindrome (41114441114).

The spelling of 10110240013 in words is "ten billion, one hundred ten million, two hundred forty thousand, thirteen".