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101103028319 is a prime number
BaseRepresentation
bin101111000101000110…
…1011100100001011111
3100122222001011222122102
41132022031130201133
53124024333401234
6114240204435315
710206266363336
oct1361215344137
9318861158572
10101103028319
1139972029657
1217717248b3b
1396c31b0917
144c7174ad1d
15296aebcc7e
hex178a35c85f

101103028319 has 2 divisors, whose sum is σ = 101103028320. Its totient is φ = 101103028318.

The previous prime is 101103028283. The next prime is 101103028321. The reversal of 101103028319 is 913820301101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101103028319 - 28 = 101103028063 is a prime.

It is a super-2 number, since 2×1011030283192 (a number of 23 digits) contains 22 as substring.

Together with 101103028321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101103028291 and 101103028300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101103028339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551514159 + 50551514160.

It is an arithmetic number, because the mean of its divisors is an integer number (50551514160).

Almost surely, 2101103028319 is an apocalyptic number.

101103028319 is a deficient number, since it is larger than the sum of its proper divisors (1).

101103028319 is an equidigital number, since it uses as much as digits as its factorization.

101103028319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 29.

The spelling of 101103028319 in words is "one hundred one billion, one hundred three million, twenty-eight thousand, three hundred nineteen".