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101103113 is a prime number
BaseRepresentation
bin1100000011010…
…11011000001001
321001020120101202
412001223120021
5201340244423
614010553545
72335235156
oct601533011
9231216352
10101103113
11520852a1
1229a388b5
1317c3b937
14d5db22d
158d21728
hex606b609

101103113 has 2 divisors, whose sum is σ = 101103114. Its totient is φ = 101103112.

The previous prime is 101103109. The next prime is 101103143. The reversal of 101103113 is 311301101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81504784 + 19598329 = 9028^2 + 4427^2 .

It is a cyclic number.

It is not a de Polignac number, because 101103113 - 22 = 101103109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101103094 and 101103103.

It is not a weakly prime, because it can be changed into another prime (101103143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551556 + 50551557.

It is an arithmetic number, because the mean of its divisors is an integer number (50551557).

Almost surely, 2101103113 is an apocalyptic number.

It is an amenable number.

101103113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101103113 is an equidigital number, since it uses as much as digits as its factorization.

101103113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 11.

The square root of 101103113 is about 10055.0043759314. The cubic root of 101103113 is about 465.8593781399.

Adding to 101103113 its reverse (311301101), we get a palindrome (412404214).

The spelling of 101103113 in words is "one hundred one million, one hundred three thousand, one hundred thirteen".