10110313111 has 2 divisors, whose sum is σ = 10110313112. Its totient is φ = 10110313110.

The previous prime is 10110313097. The next prime is 10110313127. The reversal of 10110313111 is 11131301101.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10110313111 is a prime.

It is a super-3 number, since 3×10110313111³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10110313091 and 10110313100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110313511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055156555 + 5055156556.

It is an arithmetic number, because the mean of its divisors is an integer number (5055156556).

Almost surely, 2^10110313111 is an apocalyptic number.

10110313111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110313111 is an equidigital number, since it uses as much as digits as its factorization.

10110313111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 10110313111 its reverse (11131301101), we get a palindrome (21241614212).

The spelling of 10110313111 in words is "ten billion, one hundred ten million, three hundred thirteen thousand, one hundred eleven".