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101103222013 = 439230303467
BaseRepresentation
bin101111000101000111…
…0001011110011111101
3100122222001112211100021
41132022032023303331
53124024411101023
6114240212532141
710206301131133
oct1361216136375
9318861484307
10101103222013
1139972151132
1217717321051
1396c324ab31
144c7179b753
15296b00a35d
hex178a38bcfd

101103222013 has 4 divisors (see below), whose sum is σ = 101333525920. Its totient is φ = 100872918108.

The previous prime is 101103221993. The next prime is 101103222037. The reversal of 101103222013 is 310222301101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101103222013 - 213 = 101103213821 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101103222043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115151295 + ... + 115152172.

It is an arithmetic number, because the mean of its divisors is an integer number (25333381480).

Almost surely, 2101103222013 is an apocalyptic number.

It is an amenable number.

101103222013 is a deficient number, since it is larger than the sum of its proper divisors (230303907).

101103222013 is an equidigital number, since it uses as much as digits as its factorization.

101103222013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 230303906.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 101103222013 its reverse (310222301101), we get a palindrome (411325523114).

The spelling of 101103222013 in words is "one hundred one billion, one hundred three million, two hundred twenty-two thousand, thirteen".

Divisors: 1 439 230303467 101103222013