101110000111013 has 2 divisors, whose sum is σ = 101110000111014. Its totient is φ = 101110000111012.

The previous prime is 101110000110949. The next prime is 101110000111063. The reversal of 101110000111013 is 310111000011101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95898285516289 + 5211714594724 = 9792767^2 + 2282918^2 .

It is an emirp because it is prime and its reverse (310111000011101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101110000111013 - 2⁶ = 101110000110949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101110000110985 and 101110000111003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101110000111063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555000055506 + 50555000055507.

It is an arithmetic number, because the mean of its divisors is an integer number (50555000055507).

Almost surely, 2^{101110000111013} is an apocalyptic number.

It is an amenable number.

101110000111013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101110000111013 is an equidigital number, since it uses as much as digits as its factorization.

101110000111013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 101110000111013 its reverse (310111000011101), we get a palindrome (411221000122114).

It can be divided in two parts, 10111000011101 and 3, that multiplied together give a palindrome (30333000033303).

The spelling of 101110000111013 in words is "one hundred one trillion, one hundred ten billion, one hundred eleven thousand, thirteen".