1011102020113 has 4 divisors (see below), whose sum is σ = 1011104658928. Its totient is φ = 1011099381300.

The previous prime is 1011102020069. The next prime is 1011102020119. The reversal of 1011102020113 is 3110202011101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011102020113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011102020093 and 1011102020102.

It is not an unprimeable number, because it can be changed into a prime (1011102020119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 621663 + ... + 1551988.

It is an arithmetic number, because the mean of its divisors is an integer number (252776164732).

Almost surely, 2^{1011102020113} is an apocalyptic number.

It is an amenable number.

1011102020113 is a deficient number, since it is larger than the sum of its proper divisors (2638815).

1011102020113 is an equidigital number, since it uses as much as digits as its factorization.

1011102020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2638814.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1011102020113 its reverse (3110202011101), we get a palindrome (4121304031214).

The spelling of 1011102020113 in words is "one trillion, eleven billion, one hundred two million, twenty thousand, one hundred thirteen".