Base | Representation |
---|---|
bin | 1001001100100010100001… |
… | …1110001111111101100010 |
3 | 1022210121100012120221111102 |
4 | 2103020220132033331202 |
5 | 2311124343200024442 |
6 | 33300535522514402 |
7 | 2062332541142546 |
oct | 223105036177542 |
9 | 38717305527442 |
10 | 10111032033122 |
11 | 3249078a96969 |
12 | 1173704205a02 |
13 | 58460a3c9ac7 |
14 | 26d53b3dba26 |
15 | 128027948232 |
hex | 9322878ff62 |
10111032033122 has 4 divisors (see below), whose sum is σ = 15166548049686. Its totient is φ = 5055516016560.
The previous prime is 10111032033103. The next prime is 10111032033139. The reversal of 10111032033122 is 22133023011101.
It is a happy number.
10111032033122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10071032433121 + 39999600001 = 3173489^2 + 199999^2 .
It is a junction number, because it is equal to n+sod(n) for n = 10111032033094 and 10111032033103.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527758008279 + ... + 2527758008282.
Almost surely, 210111032033122 is an apocalyptic number.
10111032033122 is a deficient number, since it is larger than the sum of its proper divisors (5055516016564).
10111032033122 is an equidigital number, since it uses as much as digits as its factorization.
10111032033122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5055516016563.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 10111032033122 its reverse (22133023011101), we get a palindrome (32244055044223).
The spelling of 10111032033122 in words is "ten trillion, one hundred eleven billion, thirty-two million, thirty-three thousand, one hundred twenty-two".
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