1011111130013 has 2 divisors, whose sum is σ = 1011111130014. Its totient is φ = 1011111130012.

The previous prime is 1011111130009. The next prime is 1011111130027. The reversal of 1011111130013 is 3100311111101.

It is an a-pointer prime, because the next prime (1011111130027) can be obtained adding 1011111130013 to its sum of digits (14).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1006887819844 + 4223310169 = 1003438^2 + 64987^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011111130013 - 2² = 1011111130009 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1011111130013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011111130093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505555565006 + 505555565007.

It is an arithmetic number, because the mean of its divisors is an integer number (505555565007).

Almost surely, 2^{1011111130013} is an apocalyptic number.

It is an amenable number.

1011111130013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011111130013 is an equidigital number, since it uses as much as digits as its factorization.

1011111130013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 14.

Adding to 1011111130013 its reverse (3100311111101), we get a palindrome (4111422241114).

The spelling of 1011111130013 in words is "one trillion, eleven billion, one hundred eleven million, one hundred thirty thousand, thirteen".