101112120000011 has 4 divisors (see below), whose sum is σ = 101457212560032. Its totient is φ = 100767027439992.

The previous prime is 101112120000007. The next prime is 101112120000109. The reversal of 101112120000011 is 110000021211101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101112120000011 - 2² = 101112120000007 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101112119999947 and 101112120000001.

It is not an unprimeable number, because it can be changed into a prime (101112120030011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172546279571 + ... + 172546280156.

It is an arithmetic number, because the mean of its divisors is an integer number (25364303140008).

Almost surely, 2^{101112120000011} is an apocalyptic number.

101112120000011 is a deficient number, since it is larger than the sum of its proper divisors (345092560021).

101112120000011 is an equidigital number, since it uses as much as digits as its factorization.

101112120000011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 345092560020.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 101112120000011 its reverse (110000021211101), we get a palindrome (211112141211112).

The spelling of 101112120000011 in words is "one hundred one trillion, one hundred twelve billion, one hundred twenty million, eleven", and thus it is an aban number.