1011121212133 has 2 divisors, whose sum is σ = 1011121212134. Its totient is φ = 1011121212132.

The previous prime is 1011121212109. The next prime is 1011121212181. The reversal of 1011121212133 is 3312121211101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 920615303169 + 90505908964 = 959487^2 + 300842^2 .

It is an emirp because it is prime and its reverse (3312121211101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1011121212133 - 2³⁷ = 873682258661 is a prime.

It is a super-2 number, since 2×1011121212133² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1011121212133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011121212733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505560606066 + 505560606067.

It is an arithmetic number, because the mean of its divisors is an integer number (505560606067).

Almost surely, 2^{1011121212133} is an apocalyptic number.

It is an amenable number.

1011121212133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011121212133 is an equidigital number, since it uses as much as digits as its factorization.

1011121212133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1011121212133 its reverse (3312121211101), we get a palindrome (4323242423234).

The spelling of 1011121212133 in words is "one trillion, eleven billion, one hundred twenty-one million, two hundred twelve thousand, one hundred thirty-three".