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1011121221157 is a prime number
BaseRepresentation
bin11101011011010111000…
…01010110111000100101
310120122212202221222212221
432231223201112320211
5113031234013034112
62052300324512341
7133023345400225
oct16555341267045
93518782858787
101011121221157
1135a8a5629a63
12143b6654b6b1
137446b356b88
1436d1d470085
151b47cc9ce07
hexeb6b856e25

1011121221157 has 2 divisors, whose sum is σ = 1011121221158. Its totient is φ = 1011121221156.

The previous prime is 1011121221031. The next prime is 1011121221161. The reversal of 1011121221157 is 7511221211101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1007963792676 + 3157428481 = 1003974^2 + 56191^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1011121221157 is a prime.

It is a super-2 number, since 2×10111212211572 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011121221857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505560610578 + 505560610579.

It is an arithmetic number, because the mean of its divisors is an integer number (505560610579).

Almost surely, 21011121221157 is an apocalyptic number.

It is an amenable number.

1011121221157 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011121221157 is an equidigital number, since it uses as much as digits as its factorization.

1011121221157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 280, while the sum is 25.

Adding to 1011121221157 its reverse (7511221211101), we get a palindrome (8522342432258).

The spelling of 1011121221157 in words is "one trillion, eleven billion, one hundred twenty-one million, two hundred twenty-one thousand, one hundred fifty-seven".