Base | Representation |
---|---|
bin | 11101011011010111000… |
… | …01010110110110100111 |
3 | 10120122212202221222201021 |
4 | 32231223201112312213 |
5 | 113031234013033111 |
6 | 2052300324512011 |
7 | 133023345366655 |
oct | 16555341266647 |
9 | 3518782858637 |
10 | 1011121221031 |
11 | 35a8a5629959 |
12 | 143b6654b607 |
13 | 7446b356abc |
14 | 36d1d46ddd5 |
15 | 1b47cc9cd71 |
hex | eb6b856da7 |
1011121221031 has 2 divisors, whose sum is σ = 1011121221032. Its totient is φ = 1011121221030.
The previous prime is 1011121221023. The next prime is 1011121221157. The reversal of 1011121221031 is 1301221211101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1011121221031 - 23 = 1011121221023 is a prime.
It is a super-2 number, since 2×10111212210312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1011121220996 and 1011121221014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011121201031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505560610515 + 505560610516.
It is an arithmetic number, because the mean of its divisors is an integer number (505560610516).
Almost surely, 21011121221031 is an apocalyptic number.
1011121221031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011121221031 is an equidigital number, since it uses as much as digits as its factorization.
1011121221031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 1011121221031 its reverse (1301221211101), we get a palindrome (2312342432132).
The spelling of 1011121221031 in words is "one trillion, eleven billion, one hundred twenty-one million, two hundred twenty-one thousand, thirty-one".
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