Base | Representation |
---|---|
bin | 11101011011010111011… |
… | …01001110001101010000 |
3 | 10120122212222211000021001 |
4 | 32231223231032031100 |
5 | 113031240312100334 |
6 | 2052300515311344 |
7 | 133023414002641 |
oct | 16555355161520 |
9 | 3518788730231 |
10 | 1011124331344 |
11 | 35a8a7363766 |
12 | 143b675ab554 |
13 | 7446bba571a |
14 | 36d1da3d6c8 |
15 | 1b47d1b4714 |
hex | eb6bb4e350 |
1011124331344 has 20 divisors (see below), whose sum is σ = 1961272052896. Its totient is φ = 504989608032.
The previous prime is 1011124331267. The next prime is 1011124331359. The reversal of 1011124331344 is 4431334211101.
It is a super-2 number, since 2×10111243313442 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35770284 + ... + 35798539.
Almost surely, 21011124331344 is an apocalyptic number.
It is an amenable number.
1011124331344 is a deficient number, since it is larger than the sum of its proper divisors (950147721552).
1011124331344 is an equidigital number, since it uses as much as digits as its factorization.
1011124331344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71569714 (or 71569708 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 1011124331344 its reverse (4431334211101), we get a palindrome (5442458542445).
The spelling of 1011124331344 in words is "one trillion, eleven billion, one hundred twenty-four million, three hundred thirty-one thousand, three hundred forty-four".
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