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1011130021003 = 3373000385819
BaseRepresentation
bin11101011011011000000…
…10111011010010001011
310120122220101112002000011
432231230002323102023
5113031243241133003
62052301241252351
7133023513240604
oct16555402732213
93518811462004
101011130021003
1135a8aa59a463
12143b694940b7
137447011839b
1436d206c0dab
151b47d93a46d
hexeb6c0bb48b

1011130021003 has 4 divisors (see below), whose sum is σ = 1014130407160. Its totient is φ = 1008129634848.

The previous prime is 1011130021001. The next prime is 1011130021007. The reversal of 1011130021003 is 3001200311101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1011130021003 - 21 = 1011130021001 is a prime.

It is a super-2 number, since 2×10111300210032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1011130021001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1500192573 + ... + 1500193246.

It is an arithmetic number, because the mean of its divisors is an integer number (253532601790).

Almost surely, 21011130021003 is an apocalyptic number.

1011130021003 is a deficient number, since it is larger than the sum of its proper divisors (3000386157).

1011130021003 is an equidigital number, since it uses as much as digits as its factorization.

1011130021003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3000386156.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1011130021003 its reverse (3001200311101), we get a palindrome (4012330332104).

The spelling of 1011130021003 in words is "one trillion, eleven billion, one hundred thirty million, twenty-one thousand, three".

Divisors: 1 337 3000385819 1011130021003