Base | Representation |
---|---|
bin | 11101011011011000000… |
… | …10111011010010001111 |
3 | 10120122220101112002000022 |
4 | 32231230002323102033 |
5 | 113031243241133012 |
6 | 2052301241252355 |
7 | 133023513240611 |
oct | 16555402732217 |
9 | 3518811462008 |
10 | 1011130021007 |
11 | 35a8aa59a467 |
12 | 143b694940bb |
13 | 744701183a2 |
14 | 36d206c0db1 |
15 | 1b47d93a472 |
hex | eb6c0bb48f |
1011130021007 has 2 divisors, whose sum is σ = 1011130021008. Its totient is φ = 1011130021006.
The previous prime is 1011130021001. The next prime is 1011130021009. The reversal of 1011130021007 is 7001200311101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011130021007 - 220 = 1011128972431 is a prime.
It is a super-2 number, since 2×10111300210072 (a number of 25 digits) contains 22 as substring.
Together with 1011130021009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011130021001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505565010503 + 505565010504.
It is an arithmetic number, because the mean of its divisors is an integer number (505565010504).
Almost surely, 21011130021007 is an apocalyptic number.
1011130021007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011130021007 is an equidigital number, since it uses as much as digits as its factorization.
1011130021007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 17.
Adding to 1011130021007 its reverse (7001200311101), we get a palindrome (8012330332108).
The spelling of 1011130021007 in words is "one trillion, eleven billion, one hundred thirty million, twenty-one thousand, seven".
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