Search a number
-
+
101113120023 = 3136724655723
BaseRepresentation
bin101111000101011001…
…1111100010100010111
3100122222202011200212020
41132022303330110113
53124034424320043
6114241205024223
710206451224246
oct1361263742427
9318882150766
10101113120023
11399777a1703
121771a6b5073
1396c5305146
144c72c1695d
15296bd12e83
hex178acfc517

101113120023 has 8 divisors (see below), whose sum is σ = 134916121728. Its totient is φ = 67359432504.

The previous prime is 101113119931. The next prime is 101113120037. The reversal of 101113120023 is 320021311101.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 101113120023 - 224 = 101096342807 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101113119984 and 101113120011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101113120063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12323761 + ... + 12331962.

It is an arithmetic number, because the mean of its divisors is an integer number (16864515216).

Almost surely, 2101113120023 is an apocalyptic number.

101113120023 is a deficient number, since it is larger than the sum of its proper divisors (33803001705).

101113120023 is a wasteful number, since it uses less digits than its factorization.

101113120023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24657093.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 101113120023 its reverse (320021311101), we get a palindrome (421134431124).

The spelling of 101113120023 in words is "one hundred one billion, one hundred thirteen million, one hundred twenty thousand, twenty-three".

Divisors: 1 3 1367 4101 24655723 73967169 33704373341 101113120023