101113122195 has 24 divisors (see below), whose sum is σ = 175302468432. Its totient is φ = 53914776000.

The previous prime is 101113122193. The next prime is 101113122221. The reversal of 101113122195 is 591221311101.

It is a happy number.

It is not a de Polignac number, because 101113122195 - 2¹ = 101113122193 is a prime.

It is a super-3 number, since 3×101113122195³ (a number of 34 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (101113122193) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 52116 + ... + 452705.

It is an arithmetic number, because the mean of its divisors is an integer number (7304269518).

Almost surely, 2^101113122195 is an apocalyptic number.

101113122195 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

101113122195 is a deficient number, since it is larger than the sum of its proper divisors (74189346237).

101113122195 is a wasteful number, since it uses less digits than its factorization.

101113122195 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 509283 (or 509280 counting only the distinct ones).

The product of its (nonzero) digits is 540, while the sum is 27.

Adding to 101113122195 its reverse (591221311101), we get a palindrome (692334433296).

The spelling of 101113122195 in words is "one hundred one billion, one hundred thirteen million, one hundred twenty-two thousand, one hundred ninety-five".