101113132133 has 6 divisors (see below), whose sum is σ = 109489368114. Its totient is φ = 93335198736.

The previous prime is 101113132129. The next prime is 101113132163. The reversal of 101113132133 is 331231311101.

It can be written as a sum of positive squares in 3 ways, for example, as 1056055009 + 100057077124 = 32497^2 + 316318^2 .

It is not a de Polignac number, because 101113132133 - 2² = 101113132129 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101113132103) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 299151110 + ... + 299151447.

It is an arithmetic number, because the mean of its divisors is an integer number (18248228019).

Almost surely, 2^101113132133 is an apocalyptic number.

101113132133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

101113132133 is a deficient number, since it is larger than the sum of its proper divisors (8376235981).

101113132133 is an equidigital number, since it uses as much as digits as its factorization.

101113132133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 598302583 (or 598302570 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 101113132133 its reverse (331231311101), we get a palindrome (432344443234).

The spelling of 101113132133 in words is "one hundred one billion, one hundred thirteen million, one hundred thirty-two thousand, one hundred thirty-three".