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101113132993 is a prime number
BaseRepresentation
bin101111000101011001…
…1111111011111000001
3100122222202012100122121
41132022303333133001
53124034430223433
6114241205204241
710206451310125
oct1361263773701
9318882170577
10101113132993
1139977800424
121771a700681
1396c530b012
144c72c1b585
15296bd16c2d
hex178acff7c1

101113132993 has 2 divisors, whose sum is σ = 101113132994. Its totient is φ = 101113132992.

The previous prime is 101113132969. The next prime is 101113133027. The reversal of 101113132993 is 399231311101.

It is an a-pointer prime, because the next prime (101113133027) can be obtained adding 101113132993 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97883256769 + 3229876224 = 312863^2 + 56832^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101113132993 is a prime.

It is not a weakly prime, because it can be changed into another prime (101113132093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556566496 + 50556566497.

It is an arithmetic number, because the mean of its divisors is an integer number (50556566497).

Almost surely, 2101113132993 is an apocalyptic number.

It is an amenable number.

101113132993 is a deficient number, since it is larger than the sum of its proper divisors (1).

101113132993 is an equidigital number, since it uses as much as digits as its factorization.

101113132993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4374, while the sum is 34.

The spelling of 101113132993 in words is "one hundred one billion, one hundred thirteen million, one hundred thirty-two thousand, nine hundred ninety-three".