10111314541 has 2 divisors, whose sum is σ = 10111314542. Its totient is φ = 10111314540.

The previous prime is 10111314539. The next prime is 10111314559. The reversal of 10111314541 is 14541311101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9735768900 + 375545641 = 98670^2 + 19379^2 .

It is an emirp because it is prime and its reverse (14541311101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10111314541 - 2¹ = 10111314539 is a prime.

Together with 10111314539, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111314511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055657270 + 5055657271.

It is an arithmetic number, because the mean of its divisors is an integer number (5055657271).

Almost surely, 2^10111314541 is an apocalyptic number.

It is an amenable number.

10111314541 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111314541 is an equidigital number, since it uses as much as digits as its factorization.

10111314541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 10111314541 its reverse (14541311101), we get a palindrome (24652625642).

The spelling of 10111314541 in words is "ten billion, one hundred eleven million, three hundred fourteen thousand, five hundred forty-one".