1011131999 has 2 divisors, whose sum is σ = 1011132000. Its totient is φ = 1011131998.

The previous prime is 1011131993. The next prime is 1011132011. The reversal of 1011131999 is 9991311101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1011131999 - 2⁴ = 1011131983 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011131993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505565999 + 505566000.

It is an arithmetic number, because the mean of its divisors is an integer number (505566000).

Almost surely, 2^1011131999 is an apocalyptic number.

1011131999 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011131999 is an equidigital number, since it uses as much as digits as its factorization.

1011131999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2187, while the sum is 35.

The square root of 1011131999 is about 31798.3018257265. The cubic root of 1011131999 is about 1003.6969818157.

The spelling of 1011131999 in words is "one billion, eleven million, one hundred thirty-one thousand, nine hundred ninety-nine".