1011132011 has 2 divisors, whose sum is σ = 1011132012. Its totient is φ = 1011132010.

The previous prime is 1011131999. The next prime is 1011132013. The reversal of 1011132011 is 1102311101.

It is a happy number.

1011132011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011132011 is a prime.

Together with 1011132013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011131983 and 1011132001.

It is not a weakly prime, because it can be changed into another prime (1011132013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505566005 + 505566006.

It is an arithmetic number, because the mean of its divisors is an integer number (505566006).

Almost surely, 2^1011132011 is an apocalyptic number.

1011132011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011132011 is an equidigital number, since it uses as much as digits as its factorization.

1011132011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

The square root of 1011132011 is about 31798.3020144158. The cubic root of 1011132011 is about 1003.6969857863.

Adding to 1011132011 its reverse (1102311101), we get a palindrome (2113443112).

The spelling of 1011132011 in words is "one billion, eleven million, one hundred thirty-two thousand, eleven".