10111323137 has 2 divisors, whose sum is σ = 10111323138. Its totient is φ = 10111323136.

The previous prime is 10111323097. The next prime is 10111323139. The reversal of 10111323137 is 73132311101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9809119681 + 302203456 = 99041^2 + 17384^2 .

It is a cyclic number.

It is not a de Polignac number, because 10111323137 - 2¹⁶ = 10111257601 is a prime.

Together with 10111323139, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10111323139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055661568 + 5055661569.

It is an arithmetic number, because the mean of its divisors is an integer number (5055661569).

Almost surely, 2^10111323137 is an apocalyptic number.

It is an amenable number.

10111323137 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111323137 is an equidigital number, since it uses as much as digits as its factorization.

10111323137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 23.

Adding to 10111323137 its reverse (73132311101), we get a palindrome (83243634238).

The spelling of 10111323137 in words is "ten billion, one hundred eleven million, three hundred twenty-three thousand, one hundred thirty-seven".