1011200120093 has 2 divisors, whose sum is σ = 1011200120094. Its totient is φ = 1011200120092.

The previous prime is 1011200120039. The next prime is 1011200120113. The reversal of 1011200120093 is 3900210021101.

Together with previous prime (1011200120039) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (1011200120113) can be obtained adding 1011200120093 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 993185648569 + 18014471524 = 996587^2 + 134218^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011200120093 - 2¹⁸ = 1011199857949 is a prime.

It is a super-3 number, since 3×1011200120093³ (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011200120393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505600060046 + 505600060047.

It is an arithmetic number, because the mean of its divisors is an integer number (505600060047).

Almost surely, 2^{1011200120093} is an apocalyptic number.

It is an amenable number.

1011200120093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011200120093 is an equidigital number, since it uses as much as digits as its factorization.

1011200120093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1011200120093 its reverse (3900210021101), we get a palindrome (4911410141194).

The spelling of 1011200120093 in words is "one trillion, eleven billion, two hundred million, one hundred twenty thousand, ninety-three".