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10112001411 = 33370667137
BaseRepresentation
bin10010110101011100…
…01110010110000011
3222002201111220011210
421122232032112003
5131202133021121
64351223141203
7505404410451
oct113256162603
928081456153
1010112001411
114319a63366
121b625a4803
13c51c737b5
146bcd999d1
153e2b33876
hex25ab8e583

10112001411 has 4 divisors (see below), whose sum is σ = 13482668552. Its totient is φ = 6741334272.

The previous prime is 10112001407. The next prime is 10112001433. The reversal of 10112001411 is 11410021101.

10112001411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 10112001411 - 22 = 10112001407 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10112001401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685333566 + ... + 1685333571.

It is an arithmetic number, because the mean of its divisors is an integer number (3370667138).

Almost surely, 210112001411 is an apocalyptic number.

10112001411 is a deficient number, since it is larger than the sum of its proper divisors (3370667141).

10112001411 is an equidigital number, since it uses as much as digits as its factorization.

10112001411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3370667140.

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 10112001411 its reverse (11410021101), we get a palindrome (21522022512).

The spelling of 10112001411 in words is "ten billion, one hundred twelve million, one thousand, four hundred eleven".

Divisors: 1 3 3370667137 10112001411