101120020031 has 2 divisors, whose sum is σ = 101120020032. Its totient is φ = 101120020030.

The previous prime is 101120020021. The next prime is 101120020037. The reversal of 101120020031 is 130020021101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101120020031 - 2⁶ = 101120019967 is a prime.

It is a super-2 number, since 2×101120020031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101120019994 and 101120020021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101120020037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560010015 + 50560010016.

It is an arithmetic number, because the mean of its divisors is an integer number (50560010016).

Almost surely, 2^101120020031 is an apocalyptic number.

101120020031 is a deficient number, since it is larger than the sum of its proper divisors (1).

101120020031 is an equidigital number, since it uses as much as digits as its factorization.

101120020031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 101120020031 its reverse (130020021101), we get a palindrome (231140041132).

The spelling of 101120020031 in words is "one hundred one billion, one hundred twenty million, twenty thousand, thirty-one".